IPL 2020 Auctions KKR Predictions

On December 19th 2019, IPL 2020 Auctions would take place in Kolkata. With a total of 127 cricketers retained including 35 overseas players, we look at how each team stands before the auction. How much cash do each team have and how strong would they bid for the likely players.

Purse Before the Auction

Franchise  No of Players No of Overseas Players Total money spent (Rs.) Salary cap available (Rs.) Available Slots Overseas Slots
CSK 20 6 70.40 cr 14.60 cr 5 2
DC 14 3 57.15 cr 27.85 cr 11 5
KXIP 16 4 42.30 cr 42.70 cr 9 4
KKR 14 4 49.35 cr 35.65 cr 11 4
MI 18 6 71.95 cr 13.05 cr 7 2
RR 14 4 56.10 cr 28.90 cr 11 4
RCB 13 2 57.10 cr 27.90 cr 12 6
SRH 18 6 68.00 cr 17.00 cr 7 2
Total 127 35 472.3 cr 207.65 cr 73 29

IPL 2020 Auctions KKR

Team Composition

  • KKR is one of the 3 teams with a big budget of 35.65 Cr to fill 11 slots, including 4 overseas . Let’s look at the current squad before IPL 2020 Auctions KKR:
Current Squad
Home/Overseas Retained Players Role Style
Overseas Andre Russell All-rounder RA/RHB
Home Dinesh Karthik WK/BAT RHB
Overseas Harry Gurney Pacer LA
Home Kamlesh Nagarkoti Pacer RA
Home Kuldeep Yadav Spinner LA
Overseas Lockie Ferguson Pacer RA
Home Nitish Rana Batsmen LHB
Home Prasidh Krishna Pacer RA
Home Rinku Singh Batsmen LHB
Home Sandeep Warrier Pacer RA
Home Shivam Mavi Pacer RA
Home Shubman Gill Batsmen RHB
Home Siddhesh Lad BAT RHB
Overseas Sunil Narine All-rounder RA/LHB

 

With a lack of a proper opening batting pair KKR will look to buy at least 2 openers.

Kuldeep Yadav had an average year and Sunil Narine has lost a bit of his bite after the change in his action. KKR will look to bolster the spin department with a recognized spinner or a spinning all-rounder.

Kuldeep Yadav IPL

A backup wicket keeper would also be a necessity if Dinesh Karthik suffers an injury.

Dinesh Karthik KKR

An inexperienced pace attack spelt disaster for KKR last year hence addition of an experienced pacer will surely be the priority.

LEAVE A REPLY

Please enter your comment!
Please enter your name here

two × one =